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Thread: exact value equation. identity for next step?

  1. #1
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    exact value equation. identity for next step?

    hi everyone. I am stuck on which identity to apply next. I know what the next step should look like but I cant get there. could you show which idntity to apply and how? thanks

    tan2x-cotx=0

    \frac {2tanx}{1-tan^2x}-cotx=0

    (\frac {1-tan^2x}{1})\frac {2tanx}{1-tan^2x}=cotx(\frac {1-tan^2x}{1})

    2tanx=cotx-cotxtan^2x

    this is where I get stuck. how do you get to the next step? it should look like this.

    2tanx=cotx-tanx
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  2. #2
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    Try writing \displaystyle \cot{x} = \frac{1}{\tan{x}}.
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  3. #3
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    What is the definition of tan and cot?

    If you still don't see it, why not express tan and cot as sin and cos?

    EDIT: Woops, a little too late
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    o geeze... i see it now. thanks guys. really fast reply!
    I always get stuck on simple stuff. I over think things to much...

    it was good to learn how to use latex tho!
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