Results 1 to 4 of 4

Math Help - exact value equation. identity for next step?

  1. #1
    Member
    Joined
    Oct 2010
    From
    Heart of Winter
    Posts
    115
    Thanks
    1

    exact value equation. identity for next step?

    hi everyone. I am stuck on which identity to apply next. I know what the next step should look like but I cant get there. could you show which idntity to apply and how? thanks

    tan2x-cotx=0

    \frac {2tanx}{1-tan^2x}-cotx=0

    (\frac {1-tan^2x}{1})\frac {2tanx}{1-tan^2x}=cotx(\frac {1-tan^2x}{1})

    2tanx=cotx-cotxtan^2x

    this is where I get stuck. how do you get to the next step? it should look like this.

    2tanx=cotx-tanx
    Follow Math Help Forum on Facebook and Google+

  2. #2
    MHF Contributor
    Prove It's Avatar
    Joined
    Aug 2008
    Posts
    11,802
    Thanks
    1576
    Try writing \displaystyle \cot{x} = \frac{1}{\tan{x}}.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor Unknown008's Avatar
    Joined
    May 2010
    From
    Mauritius
    Posts
    1,260
    What is the definition of tan and cot?

    If you still don't see it, why not express tan and cot as sin and cos?

    EDIT: Woops, a little too late
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Member
    Joined
    Oct 2010
    From
    Heart of Winter
    Posts
    115
    Thanks
    1
    o geeze... i see it now. thanks guys. really fast reply!
    I always get stuck on simple stuff. I over think things to much...

    it was good to learn how to use latex tho!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 5
    Last Post: September 21st 2011, 01:12 AM
  2. Replies: 4
    Last Post: July 3rd 2011, 08:38 AM
  3. Next step on proving an identity.
    Posted in the Trigonometry Forum
    Replies: 2
    Last Post: October 25th 2010, 11:08 AM
  4. Replies: 3
    Last Post: October 21st 2009, 05:31 AM
  5. Multi Step Equation
    Posted in the Algebra Forum
    Replies: 1
    Last Post: October 7th 2008, 09:58 AM

Search Tags


/mathhelpforum @mathhelpforum