# Thread: Simultaneous equations involving cos and sin

1. ## Simultaneous equations involving cos and sin

$(cos \theta)x - (sin \theta)y=2$
$(sin\theta)x + (cos \theta)y=1$

In the range $0 \leq \theta < 2 \pi$ is it solvable? Or are there values of theta when the equations are not solvable?

2. Originally Posted by CuriosityCabinet
$(cos \theta)x - (sin \theta)y=2$
$(sin\theta)x + (cos \theta)y=1$

In the range $0 \leq \theta < 2 \pi$ is it solvable? Or are there values of theta when the equations are not solvable?
Assuming you mean to solve for x and y, just treat $sin(\theta)$ and $cos(\theta)$ as constants. In particular, you can multiply the first equation by $cos(\theta)$, the second equation by $sin(\theta)$, and add the equations to eliminate y. A system of equations would be "non-solvable" if and only if the resulting coefficient of x were 0. But a rather nice thing happens here!

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# eliminate tita from the following equations x=1-cos tita, y=1 sin tita

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