I'm sure this a has a simple solution, but I'm just not seeing where to start with this. 1 - $\displaystyle \frac{cos^2x}{1+sin x}$ Thank you so much!
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Originally Posted by JennyFlowers I'm sure this a has a simple solution, but I'm just not seeing where to start with this. 1 - $\displaystyle \frac{cos^2x}{1+sin x}$ Thank you so much! Use $\displaystyle Cos^2x+Sin^2x=1\Rightarrow\ Cos^2x=1-Sin^2x=(1+Sinx)(1-Sinx)$
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