Hi,

I got bad luck this term and got stuck with an instructor that doesn't even use the book to teach, so I'm really lost on this one problem.

I have to figure out the height of Mt Kilimanjaro based on two angles of elevation(they are right triangles).

One angle is 13.7 degrees, and another angle, 10.4 degrees is 5 miles behind the first. Approximate the height of mt kilimanjaro to the nearest 10th of a foot.

I have this formula so far:

$\displaystyle tan(13.7)=\frac{h}{d}$

$\displaystyle dtan(13.7) = h$

$\displaystyle d = \frac{h}{tan(13.7)}$

and

$\displaystyle tan(10.4)=\frac{h}{d+5}$

$\displaystyle (d+5)tan(10.4) = h$

$\displaystyle d+5 = \frac{h}{tan(10.4)}$

$\displaystyle d = \frac{h}{tan(10.4)}-5$

After this I'm stuck. h = height of the mountain, or the opposite side, and d = distance from the mountain; adjacent side.

I have to solve for h.

If you could explain this to me in a way that doesn't seem esoteric I'd really appreciate it..I have the solution manual with steps but it really doesn't help at all.