I know from my conic that , can you show me how I arrive at: from the above please so that I can work out my transformed conic. Thank you.
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Hello, bigroo! We have: . is in a right triangle with: . Code: * | * __ | * √17 1 | * | * | 2@ * * - - - - - - - - - - - * 4 Pythagorus says: . Therefore: .
* | * __ | * √17 1 | * | * | 2@ * * - - - - - - - - - - - * 4
Thank you soroban, it was basic Pythagorus after all. I guess I was looking too deep.
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