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Math Help - Sin X Squared & Center of gravity

  1. #1
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    Sin X Squared & Center of gravity

    Hi, I'm New to this forum so hello everyone!

    Ive been asked to find the center of gravity of Sin x squared, between the limits of 0 -180 degrees.

    I am a bit lost, once plotted how could i find the center of gravity between 0-180?

    Thanks
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  2. #2
    MHF Contributor

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    Could you tell us more about the problem? A function, such as " sin^2(x)" or " sin(x^2)" does not have a "center of gravity". That requires a physical object. A geometric object may have a "center" or "centroid" which can be calculated in the same way as a center of gravity and so called (but incorrectly in my opinion) "center of gravity". But you don't even have a geometric figure. Do you mean the center of gravity of two dimensional figure with boundary the graph of the given function and the x-axis? Or the center of gravity of the one dimensional curve? Or some other figure?

    So please: do you mean the center of
    1) The curve y= sin^2(x)

    2) The curve y= sin(x^2)

    3) The area between the graph of y= sin^2(x) and the x- axis

    4) The area between the graph of y= sin(x^2) and the x- axis

    or something else?
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  3. #3
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    thanks for your reply, apologies for not being clearer!

    it is the 4th option which I am trying to find and it would be the centroid as you put it.

    Thanks.
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