Okay, so here's what I've got:
Consider the function f(x)=sin(wx), where w is a positive constant.
If f(a) = 0 and f(b) = 1, what is the minimum possible distance between a and b?
I already have the answer to this problem (pi as in the number over 2w), however I have no idea what the process is to get to it.
If anybody knows how to solve this, please post a step-by-step guide on how to do so.
Thank you for posting, Archie. Unfortunately, I'm about as much as a layman now in math as one can get, so I'm still a little confused.
1.)You posted Sin(0+2n(pi)) = 0 and Sin((pi/2)+2n(pi)) = 1. Where did the 0 and the pi/2 come from? Are these just something that you have to memorize or use a calculator for, or is there a way to figure out what to add to 2n(pi) to get any number in a sin equation?
2.) It's obvious that "min" means "minimum," but why on earth put it there?
3.) I noticed that your answer is (pi)/2, whereas mine is (pi)/(2w). How is it that, in your answer, the "w" is somehow irrelevant?
I apolagize for my ignorance (hopefully you got a chuckle out of it), but it's been years since I had trigonometry and even the more basic stuff is barely still in my memory.
Again, thank you
You need an awareness of the graph of the function, or the "unit circle", to make sense of the question.
Also, I had a typo in my first post!! sorry
Starting at Sinx rises smoothly from 0 to 1, when or
Then the graph drops to zero when x reaches 180 degrees, continues to fall to -1 when x=270 degrees,
then rising back to zero when x reaches 360 degrees.
If however, the function is Sin(wx), then this will rise from 0 to 1 as wx goes from 0 degrees to 90 degrees.
90 degrees is the minimum distance (in degrees) required to go from 0 to 1.
It's the minimum because the graph repeatedly reaches 1 as we cycle through multiples of 360 degrees.