Thread: solving trig tangent equation.

Assuming B is a positive acute angle, find the value of B satisfying the equation tan(B + 8) = cot(2B + 22)


well its very confusing and i cant solve it

here is what ive doe

ive expanded tan (B + 8) to

(tan B tan 8 ) / ( 1-tanBtan8) = (1-tan2Btan22) / (tan 2B tan 22)

and when i cross multiply (to remove denominator,, its gets messeup,, and its wrong..

ive inputted the equation in a calculator and B is equal to 20 degrees.

can someone show me the right and completed solution for me to understand it.. simple solution will do

thanks a lot

Use the identity tan(90 - B) = cot(B)

but how

tan(B+8) = cot(2B+22) = tan(90 - 2B - 22)

B+8 = 90 - 2B - 22

Now solve for B.