You have two equation in two unknowns:
From the 2nd equaton:
, so
Put that back into the first, and solve for cos(q):
Square both sides, and rearrange:
Hello, I have a trig/physics problem from my foundations of engineering class. If this is in the wrong forum please let me know. Here it is.
Two forces P and Q with respective magnitudes 100N and 200N are are applied to the upper right corner of a crate. The sum of the two forces is a horizontal force with magnitude 250N. The the angles that P and Q make with their sum. In the picture force P is on top and force Q is below the resultant horizontal force.
So far I have taken the scalar form of the two forces and summed them to their resultant. Im calling the angles p, and q for their respective forces.
100N*COS(p)i + 100N*SIN(p)j
+200N*COS(q)i - 200N*SIN(q)j
= 250Ni
From here I am not sure where to proceed. I tried summing the individual components but I did not make any progress. Any help would be appreciated.