A golfer consistly drives a golf ball 190m. if she hits her ball down a fairway that is 83 m wide what is the maximum angle between a drive to the left and a drive to the right that would still be on the fairway.
I suggest you make a sketch of the situation.
You'll end up with a triangle with height 190 m and a perpendicular base to this height of 83m
You can half the length of the base, to get 41.5 m.
Then, you know that the angle (theta) for the between the central line and the left drive is given by:
$\displaystyle tan(\theta) = \frac{41.5}{190}$
$\displaystyle \theta = tan^{-1}(\frac{41.5}{190})$
Then, the maximum angle between the drive to the left and the drive to the right is twice that angle.
$\displaystyle Maximum\ angle = 2\theta = 2tan^{-1}(\frac{41.5}{190})$
I got $\displaystyle 24.6^o$