I suggest you make a sketch of the situation.
You'll end up with a triangle with height 190 m and a perpendicular base to this height of 83m
You can half the length of the base, to get 41.5 m.
Then, you know that the angle (theta) for the between the central line and the left drive is given by:
Then, the maximum angle between the drive to the left and the drive to the right is twice that angle.