a) Find the exact value of sin 135 by using sin (180 – 45) b) Find the exact value of sin 225 by using sin (270 – 45) b) Use the value of sin 225 found in b to find sin (–15) by using sin (225 – 240)
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Recall $\displaystyle \sin (180-\theta) = \sin \theta$ so $\displaystyle \sin 135 = \sin (180-45) = \sin 45 = \dots$
Originally Posted by pickslides Recall $\displaystyle \sin (180-\theta) = \sin \theta$ so $\displaystyle \sin 135 = \sin (180-45) = \sin 45 = \dots$ but how i can solve part c of the question
Are expected to solve the problem by using sin(A-B) = sinAcosB - cosAsinB ?
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