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What ideas have you had so far?
well ive tried to replace tangent with sin but it doesnt it.. also ive use the trig identities for 2sinBcosB (but it gets farther away) how about u
Well, I find that in proving identities of this sort, it helps if all the arguments are the same. I would probably start by using the double-angle formula on the denominator of the RHS. What does that give you?
Originally Posted by aeroflix I would multiply the numerator and denominator of the fraction by 1 - cos2B which will simplify the fraction.
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