A paperboy is riding at 10 ft/s on a bicycle and tosses a paper over his left shoulder at 50 ft/s.If the porch is 50 ft off the road, how far up the street should the paperboy release the paper to hit the porch?So i drew a diagram that looks like a right triangle (attached)

I found the hypotenuse of the triangle to be $\displaystyle \sqrt(2600) ft/s $

I figured if after he threw the paper at that speed then he would need to throw it $\displaystyle \sqrt(2600) ft $ before the porch.

It seems pretty far but i wasnt too sure about how else to go about this problem

Thank you for any help