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Math Help - Throwing an object while traveling with a speed

  1. #1
    Member mybrohshi5's Avatar
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    Throwing an object while traveling with a speed

    A paperboy is riding at 10 ft/s on a bicycle and tosses a paper over his left shoulder at 50 ft/s. If the porch is 50 ft off the road, how far up the street should the paperboy release the paper to hit the porch?

    So i drew a diagram that looks like a right triangle (attached)

    Throwing an object while traveling with a speed-img.jpg

    I found the hypotenuse of the triangle to be  \sqrt(2600) ft/s

    I figured if after he threw the paper at that speed then he would need to throw it  \sqrt(2600) ft before the porch.

    It seems pretty far but i wasnt too sure about how else to go about this problem

    Thank you for any help
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  2. #2
    Member mybrohshi5's Avatar
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    I was way over thinking this one.

    It should just be released 10 ft before the porch because in 1 second after the paper is thrown it will travel 10 ft forward and 50 ft to the left (hitting the porch)

    at least i think so haha..
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  3. #3
    Newbie
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    Al-Ain ,Abu Dhabi, UAE
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    Re: Throwing an object while traveling with a speed

    Hi
    I'm new member but i found the answer
    on yahoo so here it is:
    Call +y: direction of road, call +x: rightward direction
    g: ground, b: bike, p: paper

    Express relative motions as vectors. Neglect the vertical component of the paper's motion and assume it was the horizontal velocity that was given.
    v_b:g = 10ft/s*<0,1>
    v_p:b = 50 ft/s*<1,0>

    Add them up to find velocity of paper:
    v_p:g = v_b:g + v_p:b
    v_p:g = <50, 10> ft/s

    Express distance traveled of paper:
    d = v_p:g * t
    d = <50 * t, 10*t> ft/s

    Set target:
    d = <50 ft, x>

    find x:
    50ft = 50ft/s*t
    t = 1sec
    x = 10 ft

    Conclusion: He should throw 10 ft uproad.
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