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Math Help - inverse trig squaring

  1. #1
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    inverse trig squaring

    By squaring both sides of y=sincos^-1 (x) and using the identity sin^2 x + cos^2 x = 1. Show that y=Sqrt(1-x^2)

    I'm not sure how to square an inverse function.

    Thannk you
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  2. #2
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    Quote Originally Posted by deltaxray View Post
    By squaring both sides of y=sincos^-1 (x) and using the identity sin^2 x + cos^2 x = 1. Show that y=Sqrt(1-x^2)

    I'm not sure how to square an inverse function.

    Thannk you
    Whenever you have an inverse function, you should give it a name. That helps. Let us call \cos^{-1} (x) as \theta. This means \cos \theta = x.
    Now let us read your question. You know that y = \sin\cos^{-1} x = \sin \theta

    Now can you write \sin \theta in terms of \cos \theta and finish the problem?

    Do not forget to substitute the variable \theta back.
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  3. #3
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    thank you

    I got it
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