Hi i need help for this question. Stucked at it for a long time Given That Sec A - tan A = 2. determine the value of ( sec A + tan A ) without solving for A.
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Originally Posted by Nuts Hi i need help for this question. Stucked at it for a long time Given That Sec A - tan A = 2. determine the value of ( sec A + tan A ) without solving for A. On the one hand, (this follows from the basic Pythagorean Identity). On the other hand, it's given that . Therefore .....
Originally Posted by Nuts Hi i need help for this question. Stucked at it for a long time Given That Sec A - tan A = 2. determine the value of ( sec A + tan A ) without solving for A. We want to find from which follows the result.
Originally Posted by mr fantastic On the one hand, (this follows from the basic Pythagorean Identity). On the other hand, it's given that . Therefore ..... Hmm i do not understand how does Sec A - tan A = 2 changes to . Could you explain
Usually the easiest way to simplify trigonometric expressions is to multiply by the conjugate, then apply a trigonometric identity. In your case, you are told . Now use the Pythagorean Identity to simplify the LHS and you should be able to solve for .
Originally Posted by Archie Meade We want to find from which follows the result. Ok i solved it thanks!
Originally Posted by Nuts Ok i solved it thanks! I thought you might have tried it using Sine and Cosine, so I posted in that way. However, it's best to know the technique shown by mr fantastic and Prove It.
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