# Thread: triagular lot

1. ## triagular lot

the sides of triangular lot are 130m, 180m, 190m. the lot is to be divided by a line bisecting the largest side and drawn from the opposite vertex. find the length of the line

use law of cosines

thanks

2. Originally Posted by aeroflix
the sides of triangular lot are 130m, 180m, 190m. the lot is to be divided by a line bisecting the largest side and drawn from the opposite vertex. find the length of the line

use law of cosines

thanks
start by using the law of cosines to find the values of the three angles of the triangle ...

$\displaystyle \cos{A} = \frac{b^2+c^2-a^2}{2bc}$

then use the law of cosines again to find the length of the dividing line.

$a = \sqrt{b^2+c^2 - 2bc \cos{A}}$

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### a triangular piece of land having dimensions 130m by 180 m by 190m

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