If A+B+C=180, then prove I can prove by Since sin is positive from 0 to 180, and I can't prove the next part. Help?
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To prove sinC> sin(A-B) 2sin(C/2)cos(C/2) > 2cos([A+B)/2]*sin[(A-B)/2] sin[(A+B)/2] > sin[A-B)/2] A+B and A-B are less than 180 degrees.
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