5 sin(x+arctan(4/3)) = 3 sin x + 4 cos x (arctan is the inverse tangent) I'm really having trouble trying to prove this. I'm mainly stuck with what to do with the inverse tangent.
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Originally Posted by Rinnie 5 sin(x+arctan(4/3)) = 3 sin x + 4 cos x (arctan is the inverse tangent) I'm really having trouble trying to prove this. I'm mainly stuck with what to do with the inverse tangent. let ... using right triangle ratios, and sum identity for sine ... substitute in the values for and and finish it.
Then, of course, use .
Originally Posted by HallsofIvy Then, of course, use . fify
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