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Math Help - Trigonometric functions Factoring

  1. #1
    Aug 2010

    Trigonometric functions Factoring

    I tried to factor 1+4(\frac{1}{2}tan^2{\theta}) to be equal to  1+tan^2{\theta} but I'm having a hard time. Any tips to start me out?

    I tried to factor out 2 making it 2(\frac{1}{2}+tan^2{\theta})

    Now I'm stuck. The original equation is,

    \int{\frac{1}{1 + 4\left(\frac{1}{2}\tan{\theta}\right)^2}\left(\fra  c{1}{2}\sec^2{\theta}\right)\,d\theta}

    I need to factor the denominator so that I can apply the Trigonometric identity:
    sec^2{\theta} = 1+tan^2{\theta}
    Last edited by gamedok; August 15th 2010 at 02:42 PM. Reason: Fixed the latex
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  2. #2
    Junior Member
    Aug 2009
    1 + 4\left(\frac{1}{2}\tan{\theta}\right)^2 =1 + 4\left(\frac{1}{4}\tan^2{\theta}\right)
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  3. #3
    Aug 2010
    I feel like a ninny for missing that out.

    Thanks for the reply!
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