in a triangle ABC where a,b,c are the sides opposite to the angles A,B,C respectively AC is double of AB, then find the value of
Follow Math Help Forum on Facebook and Google+
Originally Posted by grgrsanjay in a triangle ABC where a,b,c are the sides opposite to the angles A,B,C respectively AC is double of AB, then find the value of = = Since (B+C)/2 = π/2 - A/2, sin[(B+C)/2] = cos(A/2) and cos[(B+C)/2] = sin(A/2). Substtitue these values in the above equation and simplify.
Last edited by sa-ri-ga-ma; August 11th 2010 at 11:34 PM.
View Tag Cloud