in a triangle ABC where a,b,c are the sides opposite to the angles A,B,C respectively AC is double of AB, then find the value of
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Originally Posted by grgrsanjay in a triangle ABC where a,b,c are the sides opposite to the angles A,B,C respectively AC is double of AB, then find the value of = = Since (B+C)/2 = π/2 - A/2, sin[(B+C)/2] = cos(A/2) and cos[(B+C)/2] = sin(A/2). Substtitue these values in the above equation and simplify.
Last edited by sa-ri-ga-ma; Aug 11th 2010 at 11:34 PM.
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