(CosθCotθ)/1-Sinθ - 1 = Cscθ 4(Tan^4)x + (tan^2)x - 3 = (sec^2)x[4(tan^2)x - 3] Sin(α/3)Cos(α/3) = .5Sin(2α/3)
Last edited by RosieLaird; August 5th 2010 at 03:52 PM.
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Originally Posted by RosieLaird (CosθCotθ)/1 = Cscθ 4(Tan^4)x + (tan^2)x - 3 = (sec^2)x[4(tan^2)x - 3] Sin(α/3)Cos(α/3) = .5Sin(2α/3) 1. recheck the first equation ... as you typed it, it makes no sense. 2. factor the left side ... then use the identity 3. use double angle formula for sine on the right side
Hello, RosieLaird! The left side is: . . . . .
4(Tan^4)x + (tan^2)x - 3 = (sec^2)x[4(tan^2)x - 3]
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