$\displaystyle \begin{array}{l} solve\;in\,R \\ \\ \frac{1}{{\sin ^2 x}} = \cot x + 3 \\ \end{array} $
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What steps have you taken so far?
Originally Posted by Ackbeet What steps have you taken so far? what do you mean? tanx=1 (complete)
That's a rather mystifying post. The equation you give there, tan(x) = 1, does not, by any means, have the same solutions as the equation in the original post. I'm asking what steps have you taken so far in solving your problem?
Originally Posted by fxs12 $\displaystyle \begin{array}{l} solve\;in\,R \\ \\ \frac{1}{{\sin ^2 x}} = \cot x + 3 \\ \end{array} $ couple of identities will help ... $\displaystyle \csc^2{x} = \cot{x} + 3$ $\displaystyle 1 + \cot^2{x} = \cot{x} + 3$ $\displaystyle \cot^2{x} - \cot{x} - 2 = 0$ solve the quadratic for $\displaystyle \cot{x}$ ... then for the value(s) of x
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