so there is a right triangle
90 degrees on the bottom left 39 on the bottom right
and 12.1 in length of the hypotenuse
im told to look for all side
i tried using cosine and sine but my answers were
larger than the hypotenuse
any ideas?
so there is a right triangle
90 degrees on the bottom left 39 on the bottom right
and 12.1 in length of the hypotenuse
im told to look for all side
i tried using cosine and sine but my answers were
larger than the hypotenuse
any ideas?
If your answers were larger than the hypotenuse,
then after
$\displaystyle sin39^o=\frac{opposite}{hypotenuse}=\frac{a}{12.1}$
you should get "a" by multiplying both sides by 12.1.
Did you end up with $\displaystyle a=\frac{12.1}{sin39^o}$ instead?
Also
$\displaystyle cos39^o=\frac{adjacent}{hypotenuse}=\frac{b}{12.1}$
so you get "b" by multiplying both sides by 12.1.
You will get a value larger than the hypotenuse if you look for $\displaystyle \frac{12.1}{cos39^o}$ instead.
Why is that and why multiply both sides by 12.1?
skeeter's diagram is exactly how the picture is formed
so i tried the following
cos(39)=b/12.1
but now that u mention it
i forgot to multiply "12.1" to the cos(39) and
i saw that i screwed up the problem there resulting in 9.4 instead of 15
so i think thats where i went wrong