# Rectangle Trigonometry

• May 20th 2007, 09:29 AM
Godfather
Rectangle Trigonometry
The Area of a rectangle can be given in terms of the length p of a diagonal and two trigonometric functions of an angle formed by the diagnoal and a side.Which of the following formulas gives the area A of this rectangle and why?
A. p^2 sec(O)
B. p^2 cot(O)
C. p^2 sin(O) tan(O)
D. p^2 sin(O) cos(O)
• May 20th 2007, 09:38 AM
Jhevon
Quote:

Originally Posted by Godfather
The Area of a rectangle can be given in terms of the length p of a diagonal and two trigonometric functions of an angle formed by the diagnoal and a side.Which of the following formulas gives the area A of this rectangle and why?
A. p^2 sec(O)
B. p^2 cot(O)
C. p^2 sin(O) tan(O)
D. p^2 sin(O) cos(O)

Tell me if you can figure it out from this. see the diagram below to see what A,B,C and D mean.

For a rectangle, A = length*width

now:
sin(0) = AB/p
and
cos(0) = AC/p
• May 20th 2007, 09:49 AM
Godfather
Quote:

Originally Posted by Jhevon
Tell me if you can figure it out from this. see the diagram below to see what A,B,C and D mean.

For a rectangle, A = length*width

now:
sin(0) = AB/p
and
cos(0) = AC/p

No i can't can u please explain like u did the other one
• May 20th 2007, 10:07 AM
Jhevon
Quote:

Originally Posted by Godfather
No i can't can u please explain like u did the other one

all we are doing here, is rearranging equations to get what we want. they asked about area, so we come up with the general formula for the area. since we don't have numbers, we have to use formulas to represent the components that we need.

now, for a rectangle:

A = length * width

now we need to find formulas for the length and width. if you label the vertices of the triangle as i did below, you'd realize that the length is AB and the width is AC

so the area will be given by A = AB*AC

now sine = opp/hyp and cosine = adj/hyp ........the hyp is p

=> sin(o) = AB/p => AB = psin(o)

=> cos(o) = AC/p => AC = pcos(o)

Now, A = AB*AC = psin(o) * pcos(o) = p^2 * sin(o)cos(0)