1. cosxtanx-1+tanx-cosx=0
2. 2sinxtanx- tanx- 2sinx +1 = 0
Help would be greatly appreciated
- Thank you
Here's the first one.
When faced with trig problems like these, what you want to do is first see if any trig identities can siplify things a bit. If not, treat each trig function as a variable, and facter as you would normally. for instance, the first one is:
tan^2x - 4tanx = 0
if we thought of tangent as a variable, say y, the problem would become:
y^2 - 4y = 0
that's a regular quadratic equation, you should have no problem with that. that is the basis of how i approached the problem. try the second one and tell me if you get it
EDIT: i see that you changed question 1. anyway, it doesn't matter, the same method is applicable. try them
yeah i was kind of over thinking the problem that i changed, cause just as i posted it i figured out how easy it was. But for the other ones im not sure if im going in the right direction, for ex #2
2sinxtanx- tanx- 2sinx +1 = 0
2sin²/cosx - sinx/cosx - 2sinxcosx/cosx + cosx/cosx= 0
is that what i should be doing? or am i over doing it again? lol
yes, you are over doing it again i'm afraid, lol. calm down
2sinxtanx - tanx - 2sinx + 1 = 0 .......factor out the common term from each pair
=> tanx(2sinx - 1) - (2sinx - 1) = 0 ....now we have a common 2sinx - 1, factor it out
=> (2sinx - 1)(tanx - 1) = 0
can you take it from here?
yeah, a lot of students get paranoid with trig. just calm down, take a deep breath and approach them with a cool head. if seeing trig makes you sqirm, just replaced them with a variable as i suggested earlier, and you will be able to think straight. another thing that often scares students is logarithms, especially ones that involve ln and e, don't fall into that trap