1. ## Trigonometric equation

Can anybody help me with this equation? I am staring to think there is a mistake there....
I tried to factor it, but it does not seem right...

2sin^2(x) - 6sin(x)- 3=0

2. Hint:

3. Hint 2:

$\displaystyle |sin(x)| \leq 1$

4. This is what I tried:
sinx=t
2t^2-6t-3=o
I used quadratic formula, and got:
t= ( 3- √15) /2 = -0.43

What now? I could substitute t for sinx now, but it does not help...

5. Originally Posted by Angie80
This is what I tried:
sinx=t
2t^2-6t-3=o
I used quadratic formula, and got:
t= ( 3- √15) /2 = -0.43

What now? I could substitute t for sinx now, but it does not help...
Exact solutions:

Let $\displaystyle x_1 = \frac{3 - \sqrt{15}}{2}$. Then $\displaystyle \sin (x) = x_1 \Rightarrow x = \sin^{-1} (x_1) + 2 n \pi$ or $\displaystyle x = \sin^{-1} (-x_1) + \pi + 2 n \pi$ (using the symmetry of the unit circle) where n is an integer.

Approximate solutions:

Use a calculator to get a decimal approximation of $\displaystyle \sin^{-1} \left( \frac{3 - \sqrt{15}}{2} \right)$ and then proceed in the usual way.

6. So, I calculated it and got appx: -26
I must be missing something, because I really do not know how to proceed from here...
I know how to use unit circle, but what is value of x, when sinx=-26??

I am veeery confused now....

7. Originally Posted by Angie80
So, I calculated it and got appx: -26
I must be missing something, because I really do not know how to proceed from here...
I know how to use unit circle, but what is value of x, when sinx=-26?? Mr F says: No. x = -26, not sinx.

I am veeery confused now....
sin is negative in the 3rd and 4th quadrants. Using degrees, in the 4th quadrant, x = -26 + (360)n. In the 3rd quadrant, x = (180 + 26) + (360)n by symmetry of the unit circle.

Go back and review examples from your class notes and textbook.

8. Thanks soooo much!