Find the trigonometric limit: lim (as x approaches infinity) (x-tan 2x)/sin 2x
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Originally Posted by bobby77 Find the trigonometric limit: lim (as x approaches infinity) (x-tan 2x)/sin 2x Are you sure you have this right? What you have written does not have a limit as x tends to infinity. RonL
Hi, do you mean maybe: lim(as x approaches zero)(x-tan2x)/(sin(2x)) ??? If so $\displaystyle \lim_\subc{x \rightarrow 0} {\frac{x-\tan{2x}}{\sin{2x}} =-\frac{1}{2}$
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