Find the trigonometric limit: lim (as x approaches infinity) (x-tan 2x)/sin 2x

2. Originally Posted by bobby77
Find the trigonometric limit: lim (as x approaches infinity) (x-tan 2x)/sin 2x
Are you sure you have this right? What you have written does not have
a limit as x tends to infinity.

RonL

3. Hi,
do you mean maybe:
lim(as x approaches zero)(x-tan2x)/(sin(2x)) ???

If so
$\lim_\subc{x \rightarrow 0} {\frac{x-\tan{2x}}{\sin{2x}} =-\frac{1}{2}$