1. ## Trig problem

Solve 2sinx^2 - 7sinx= -3 for x, where 0< x < 360 degrees.

2. Originally Posted by brewerangel

Solve 2sinx^2 - 7sinx= -3 for x, where 0< x < 360 degrees.
This is a quadratic in sin(x), so put y=sin(x), then we have:

2 y^2 -7 y +3 =0,

use the quadratic formula to find that y=1/2 or y= 3.

Now there are no angles in the given range for which sin(x)=3 so we need
only examine y = sin(x) =1/2, which has solutions x=30, and x= 150 degrees
in the given range.

RonL