I think the 2x has something to do with why I can't solve this problem, but even then, I still don't remember what to do about it...
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Originally Posted by orkdork I think the 2x has something to do with why I can't solve this problem, but even then, I still don't remember what to do about it... Create a right triangle that satisfies . Then find using the triangle constructed. Can you proceed?
I think I get it, i'll try it
Ok, yeah, I don't know how to find the right triangle... ._.
Originally Posted by orkdork Ok, yeah, I don't know how to find the right triangle... ._. Recall . So in the case of , 2x is the side opposite of , and 1 is the side adjacent to . As a result, the hypotenuse of the triangle is (verify). Now what is ?
ohh...ok that makes sense now thanks
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