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Math Help - Right Triangle

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    Right Triangle

    In a right angled triangle ABC shown below, tan(angle ABC) = 1/2 and AB(hypotense)=square root of 20cm. Using simultaneous equations, find the length of AC(opposite) and BC(adjacent).
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  2. #2
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    Quote Originally Posted by soni View Post
    In a right angled triangle ABC shown below, tan(angle ABC) = 1/2 and AB(hypotense)=square root of 20cm. Using simultaneous equations, find the length of AC(opposite) and BC(adjacent).
    You are told that \tan{\theta} = \frac{1}{2}.

    So \frac{O}{A} = \frac{1}{2}.



    You also have, by Pythagoras' Theorem

    O^2 + A^2 = H^2

    O^2 + A^2 = (\sqrt{20})^2

    O^2 + A^2 = 20.



    So solve \frac{O}{A} = \frac{1}{2} and O^2 + A^2 = 20 simultaneously.
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