Ive run into a point I cant seem to figure out. Where do I go from where I stopped at cos^2(x/2)= 6/14??
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Originally Posted by ninobrn99 Ive run into a point I cant seem to figure out. Where do I go from where I stopped at cos^2(x/2)= 6/14?? since x is in quad II , which value works?
okay, Im not crazy then. I came up with that b4, but it wasn't one of my answer choices. Since x is in quad 2, then cos is neg and sin is posi. Thank you.
Originally Posted by ninobrn99 okay, Im not crazy then. I came up with that b4, but it wasn't one of my answer choices. Since x is in quad 2, then cos is neg and sin is posi. Thank you. for x it is ... you need to remember that the question is asking about ... care to rethink that conclusion?
Ive been staring at this problem and cant figure out what to do from there. I would think to set cos(1/2x)=-(sqrt3/7) but that doesnt work out either.
if , then ... so ?
Got it! Ugh, I've been going at this solo this past weekend trying to get ahead and was finally shown today what you meant. Thank you again for the help!