I don't know how to star solving this problem, I'm new in calculus.. f(x+y) - f(x) = sec^2 x tan y / 1 +tan x tan y
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this one sir.. given: f(x)=tan x ,show that f(x+y) - f(x) = sec^2 x tan y / 1 +tan x tan y
Whenever I have a trig identity to prove, I usually get everything in terms of sines and cosines. Use the addition of angles formulas. Then simplify.
Originally Posted by jasonlewiz this one sir.. given: f(x)=tan x ,show that f(x+y) - f(x) = sec^2 x tan y / 1 +tan x tan y the result should be
As Ackbeet said, this is a matter of a trig identity and you can reduce to sine and cosine. Now, divide both numerator and denominator by cos(x)cos(y) So that Note that, as skeeter said, you have the sign in the denominator wrong.
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