1. By "where do they solve it", I mean "where are the solutions?" You've found them. There's really only one step left. What do you suppose that is?

2. Originally Posted by Ackbeet
By "where do they solve it", I mean "where are the solutions?" You've found them. There's really only one step left. What do you suppose that is?
provide a general solution?
show that these values of x satisfy the original equation?

3. You've found the locations where the line y = x equals the original function. But how do you know that, at those points, y = x touches the original function?

4. Originally Posted by Ackbeet
You've found the locations where the line y = x equals the original function. But how do you know that, at those points, y = x touches the original function?
at the points where y=x touches the original function the gradients are equal

5. True... but how do you know that?

6. Originally Posted by Ackbeet
True... but how do you know that?
ermm.. because the line y=x is a tangent to the curve? Thus at the point where it is a tangent its gradient is equal to that of the curve?

I'm sorry Im doing really bad with this one!

7. Hint: evaluate the _____________ at the points of touching, and show that they're all equal to __ .

8. Originally Posted by Ackbeet
Hint: evaluate the _____________ at the points of touching, and show that they're all equal to __ .
evaluate the gradient at the points of touching, and show that they're all equal to 1?

ie. when x = 5pi/2, dy/dx = 1
when x = 9pi/2, dy/dx = 1
...

9. You got it. I would say that once you've shown all that, you're done with this problem.

10. Thank you soooo much! You've been such a great help

11. You're very welcome. Have a good one!

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