prove the following identities.

**mastermin346** · June 22nd 2010, 10:43 PM

please help me with this question:

a) $\frac{cot\theta}{tan\theta}+1=cosec^2\theta$

b) $\frac{1+sin\theta}{cos\theta}+\frac{cos\theta}{1+s in\theta}=2 sec\theta.$

please help!

**Prove It** · June 22nd 2010, 11:03 PM

a) $\frac{\cot{\theta}}{\tan{\theta}} + 1 = \frac{\cot{\theta}}{\frac{1}{\cot{\theta}}} + 1$

$= \cot^2{\theta} + 1$

$= \csc^2{\theta}$ .

**Prove It** · June 22nd 2010, 11:08 PM

b) $\frac{1 + \sin{\theta}}{\cos{\theta}} + \frac{\cos{\theta}}{1 + \sin{\theta}} = \frac{\cos{\theta}(1 + \sin{\theta})}{\cos^2{\theta}} + \frac{\cos{\theta}(1 - \sin{\theta})}{(1 + \sin{\theta})(1 - \sin{\theta})}$

$= \frac{\cos{\theta}(1 + \sin{\theta})}{\cos^2{\theta}} + \frac{\cos{\theta}(1 - \sin{\theta})}{1 - \sin^2{\theta}}$

$= \frac{\cos{\theta}(1 + \sin{\theta})}{\cos^2{\theta}} + \frac{\cos{\theta}(1 - \sin{\theta})}{\cos^2{\theta}}$

$= \frac{\cos{\theta}(1 + \sin{\theta}) + \cos{\theta}(1 - \sin{\theta})}{\cos^2{\theta}}$

$= \frac{\cos{\theta} + \cos{\theta}\sin{\theta} + \cos{\theta} - \cos{\theta}\sin{\theta}}{\cos^2{\theta}}$

$= \frac{2\cos{\theta}}{\cos^2{\theta}}$

$= \frac{2}{\cos{\theta}}$

$= 2\sec{\theta}$ .

**Unknown008** · June 22nd 2010, 11:15 PM

b) Maybe a shorter route...

$\frac{1+sin\theta}{cos\theta} + \frac{cos\theta}{1+sin\theta} = \frac{(1 + sin\theta)^2 + cos^2\theta}{cos\theta(1+sin\theta)}$

$= \frac{1 + 2sin\theta + sin^2 \theta + cos^2\theta}{cos\theta(1+sin\theta)}}$

$= \frac{2(1+sin\theta)}{cos\theta(1+sin\theta)}$

$= \frac{2}{cos\theta}$

$= 2sec\theta$

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