2sin3X = 2^1/2

for 0 ≤ x < 360

I narrowed down to 3X = 45 --> x = 15 and 3X = 135 --> x = 45; but my instructor says I am still missing 4.

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- June 21st 2010, 01:54 PMwindiaEquation
2sin3X = 2^1/2

for 0 ≤ x < 360

I narrowed down to 3X = 45 --> x = 15 and 3X = 135 --> x = 45; but my instructor says I am still missing 4. - June 21st 2010, 02:00 PMmr fantastic