Please help me to solve x: tan (3x - 10) = cot (x + 10) , 0 <= x <= 90, (in degrees)
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Originally Posted by Nico Please help me to solve x: tan (3x - 10) = cot (x + 10) , 0 <= x <= 90, (in degrees) sin (3x - 10)/cos (3x - 10) = cos (x + 10)/sin (x + 10) sin (3x - 10) sin (x +10) = cos (3x - 10) cos (x + 10) 0 = cos (3x - 10) cos (x + 10) - sin (3x - 10) sin (x +10) 0 = cos (3x - 10 + x + 10) 0 = cos 4x 4x = 90, 270 x = 22.5, 67.5
Originally Posted by Nico Please help me to solve x: tan (3x - 10) = cot (x + 10) , 0 <= x <= 90, (in degrees) Here is an easy way to get one of the solutions. Since tangent and cotangent are cofunctions. It means that they differ by 90 degrees. Thus the angle sum between the tangent and cotangent should be 90 degrees. 3x-10+x+10=90 4x=90 x=22.5
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