Thread: combinations and permutations

There are 5 women and 7 men who are reporters for a magazine. There are 6 articles that need to be written. If 6 reporters are chosen at random to write the articles, what is the probability that 3 are men and 3 are women?

I got 40,000/117,649. I'm doubting my answer because its such a huge fraction. Please let me know what you guys get and explain!!

Also, how do u do this?

A family with 5 children is selected at random. What is the probability that the family has atleast 3 boys?

Are you sure this is trigonometry?

Originally Posted by knicksfan426

I got 40,000/117,649. I'm doubting my answer because its such a huge fraction. Please let me know what you guys get and explain!!

How did you get your answer?

Originally Posted by knicksfan426

There are 5 women and 7 men who are reporters for a magazine. There are 6 articles that need to be written. If 6 reporters are chosen at random to write the articles, what is the probability that 3 are men and 3 are women?

I was thinking

Originally Posted by knicksfan426

Also, how do u do this?

A family with 5 children is selected at random. What is the probability that the family has atleast 3 boys?

It is assumed the probability of having a boy is equal to the probability of having a girl i.e. 0.5?

If so use X~ and find