y=asin(bx+c)+d

**ToXic01** · May 29th 2010, 02:18 PM

One of the questions is
y=-4sin2(x+pi/2)

how do i get it into this form
y=asin(bx+c)+d

Thanks

**galactus** · May 29th 2010, 02:32 PM

Is that $-4sin(2(x+\frac{\pi}{2}))?.$

Sometimes posters will not use ^ for power and write something like x2 for x^2. You do not mean $-4sin^{2}(x+\frac{\pi}{2})?.$

**ToXic01** · May 29th 2010, 02:34 PM

i double checked the question it is correct

**SpringFan25** · May 29th 2010, 04:04 PM

$-4sin(2(x+\frac{\pi}{2}))$

If the question really says that it is already in the required form, just expand the brackets to get

$-4sin(2x+\pi)$

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