One of the questions is y=-4sin2(x+pi/2) how do i get it into this form y=asin(bx+c)+d Thanks
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Is that $\displaystyle -4sin(2(x+\frac{\pi}{2}))?.$ Sometimes posters will not use ^ for power and write something like x2 for x^2. You do not mean $\displaystyle -4sin^{2}(x+\frac{\pi}{2})?.$
i double checked the question it is correct
$\displaystyle -4sin(2(x+\frac{\pi}{2}))$ If the question really says that it is already in the required form, just expand the brackets to get $\displaystyle -4sin(2x+\pi)$
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