Given A+B+C=90 Prove that cotA+cotB+cotC=(cotA)(cotB)(cotC) Thanks!
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Hello cyt91 Originally Posted by cyt91 Given A+B+C=90 Prove that cotA+cotB+cotC=(cotA)(cotB)(cotC) Thanks! Note first that So: , using the above result , multiplying top-and-bottom by Grandad
Hello, cyt91! Another approach . . . Given: . Prove that: . We need this identity: . Also note that: . We have: - - . Then: . . . . . . . . . . . . . Nice explanation, Grandad! .
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