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Math Help - One more simple problem

  1. #1
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    One more simple problem

    Anyway I've seem to come across another problem..

    Angle A = 25 degrees
    Side Z = 85 units
    Side Z is opposite of Angle A
    Side Y is the hypotenuse
    Side X is the adjacent

    \sin(25)=\frac {85}{y}

    I tried solving this using this method.. whatever it is..

    Step 1. \frac {\sin(25)}{1} = \frac {85}{y}

    Step 2. y\sin(25)=85

    Step 3. y=\frac {85}{\sin(25)}

    Step 4. y=-642.228

    Well... It's definately not -642.228, seeing as how the length of the side cannot be less than 1.

    Thanks again for all who contribute.
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  2. #2
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    Quote Originally Posted by Tyman2007 View Post
    Anyway I've seem to come across another problem..

    Angle A = 25 degrees
    Side Z = 85 units
    Side Z is opposite of Angle A
    Side Y is the hypotenuse
    Side X is the adjacent

    \sin(25)=\frac {85}{y}

    I tried solving this using this method.. whatever it is..

    Step 1. \frac {\sin(25)}{1} = \frac {85}{y}

    Step 2. y\sin(25)=85

    Step 3. y=\frac {85}{\sin(25)}

    Step 4. y=-642.228

    Well... It's definately not -642.228, seeing as how the length of the side cannot be less than 1.

    Thanks again for all who contribute.
    Why can't it be less than 1? If anything we know it must be bigger than 85 because the hypotenuse is the longest side.

    Either way your working is fine, I've not checked the arithmetic since I've misplaced my calculator
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  3. #3
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    Quote Originally Posted by Tyman2007 View Post
    Anyway I've seem to come across another problem..

    Angle A = 25 degrees
    Side Z = 85 units
    Side Z is opposite of Angle A
    Side Y is the hypotenuse
    Side X is the adjacent

    \sin(25)=\frac {85}{y}

    I tried solving this using this method.. whatever it is..

    Step 1. \frac {\sin(25)}{1} = \frac {85}{y}

    Step 2. y\sin(25)=85

    Step 3. y=\frac {85}{\sin(25)}

    Step 4. y=-642.228 your calculator was in radian mode

    Well... It's definately not -642.228, seeing as how the length of the side cannot be less than 1. cannot be <0

    Thanks again for all who contribute.
    There are 2{\pi} radians in a circle.
    As the angle is 25 degrees, your calculator needs to be in degree mode.
    Last edited by Archie Meade; May 28th 2010 at 02:28 PM.
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  4. #4
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    Thank you both.

    Didn't realize that my calculator was in radian mode, silly me :P
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