Help with calculating distance using tan, sin and cos please?

Hi, I am having problems with this question! I would be so grateful for some help!! :)

Question: The ship's captain located a light at an angle of elevation of 35º. The light rests atop a 40-foot lighthous. Find the distance from the ship to the shore using the values provided below.

values:

sin 35º=0.574 sin 55º=0.819

cos 35º=0.819 cos 55º=0.574

tan 35º=0.700 tan 55º=1.428

Thank you very very much!

1 Attachment(s)

Re: Help with calculating distance using tan, sin and cos please?

This problem is very easy. The figure is a right triangle composed by the corners:

1) the ship

2) the top of lighthouse

3) the shore.

The calcul are made in photos that I attached.

Attachment 23997

Re: Help with calculating distance using tan, sin and cos please?

It seems to me that you are assuming that the lighthouse is on the shore.

Many lighthouses are located off shore.

All that you can do I think is to calculate the distance to the lighthouse.

Re: Help with calculating distance using tan, sin and cos please?

Yes, that's true. And to find out what's the distance to the land, in naval books it's specificated the placement of lighthouses relative to shore.

Re: Help with calculating distance using tan, sin and cos please?

Yes, and that only helps if the lighthouse is on a direct line, otherwise it's a dogleg to the beach !

Re: Help with calculating distance using tan, sin and cos please?

let the distance between ship and shore is 'x' and the distance between captain and the light house is 'y'(at an elevation 35º.

sin = opposite/hypotenuse

cos = adjacent/hypotenuse

so

sin 35º = 40/y

0.574 = 40/y

y = 40/0.574

y= 40000/574

y=69.6

cos 35 = x/y

0.819 = x/69.6

x=0.819 * 69.6

x= 57

So the distance from the ship to the shore is 57

Re: Help with calculating distance using tan, sin and cos please?

What is the height of the captains eye?