A parallelogram has two adjacent sides of length 4 cm and 6 cm respectively. If the included angle measures 52 degrees, find the area of the parallelogram.

please show all working out.

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- May 26th 2010, 02:46 AMTessarinaAreas of Triangles
A parallelogram has two adjacent sides of length 4 cm and 6 cm respectively. If the included angle measures 52 degrees, find the area of the parallelogram.

please show all working out. - May 26th 2010, 04:31 AMskeeter
if $\displaystyle a$ and $\displaystyle b$ are the lengths of two adjacent sides of a parallelogram and $\displaystyle \theta$ is the included angle between those two sides, then the area of the parallelogram is given by

$\displaystyle

A = a \cdot b \cdot \sin{\theta}

$ - Aug 20th 2010, 04:43 AMumangarora
../------------|--/

/Theta------- |/

6cm

Area of a parallelogram is given by Base into corresponding altitude..k?

Now, draw perpendicular to one side.. the other side is found out by:

sin theta=opposite leg

--------------

hypotenuse

multiplying sin theta by hypotenuse gives us opposite leg.. which in the case of the triangle with one vertex, theta and altitude.. is the altitude..

so area=a.b.sin theta

=4*6*sin 52 - Aug 21st 2010, 10:37 PMEducated
The area of a triangle is:

$\displaystyle A = \frac{1}{2}a * b * \sin{C}$

From your parallelogram, there are 2 identical triangles if you divide your parallelogram in half.

From your information, a = 4, b = 6, C = $\displaystyle 54^{\circ}$.

There you can work out the area of a triangle, then double it to find the area of your parallelogram.