Hello again. I´m stuck again.. How do i solve: $\displaystyle sin(2y)=0.5$ should i make it in a form of $\displaystyle y= sin...$?? Best Regards
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Originally Posted by DenOnde Hello again. I´m stuck again.. How do i solve: $\displaystyle sin(2y)=0.5$ should i make it in a form of $\displaystyle y= sin...$?? Best Regards $\displaystyle 2y = \frac{\pi}{6} + 2n \pi$ or $\displaystyle 2y = \frac{5\pi}{6} + 2n \pi$ where $\displaystyle n \in Z$. Therefore ....
so i should take $\displaystyle y = (\pi/6)+n*\pi/2$ ? thank you for the quick reply btw
Originally Posted by DenOnde so i should take $\displaystyle y = (\pi/6)+n*\pi/2$ ? thank you for the quick reply btw No. You have not correctly divided by 2 both sides of the two general solutions I set up.
But i don't really understand where the other solution come from?
Originally Posted by DenOnde But i don't really understand where the other solution come from? Draw a unit circle. Then see that the sine of an angle is positive in quadrant 1 and quadrant 2.
ah.... of course... if you have it in degrees it's equal to 180-30 therefor the second solution? so next i should divide both solutions by 2? thank you for your patience
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