two different values for angle A ?

Hello misspalmer

Welcome to Math Help Forum!

Quote:

Originally Posted by misspalmer

Okay so here is the question

Each angle of A is between 0 degrees and 180 degrees. Which equations result in two different values for angle A ?

-sin A = .7071
-cos A = -.5
-sin A = .9269
-cos A = -.7071
-sin A = .8660
-cos A = -1
-sin A = 3/4
-cos A = 3/4
-cos A = -3/4

I would like how you got there as well ! thanks !

First, I assume that the hyphens at the left-hand end of each equation are not minus signs. You do need to be careful in writing down the questions!

Then you need to know how sine and cosine behave between $0^o$ and $180^o$ . So take a look at the diagram I've attached.

You'll see that $\sin x$ goes from $0$ to $1$ as $x$ goes from $0^o$ to $90^o$ . Then, in a symmetrical way, it goes back down to $0$ as $x$ goes from $90^o$ to $180^o$ .

So, for any number between $0$ and $1$ , there will be two angles whose sine is this number: one between $0^o$ and $90^o$ and one between $90^o$ and $180^o$ . But if the number lies outside the range $0$ to $1$ , there won't be any angles between $0^o$ and $180^o$ having this number as their sine.

On the other hand, $\cos x$ starts at $1$ and goes down to $0$ as $x$ goes from $0^o$ to $90^o$ . Then it continues down to ${-1}$ as $x$ goes from $90^o$ to $180^o$ .

So no value of $\cos x$ is repeated as $x$ takes values between $0^o$ and $180^o$ . So none of the equations involving cosine will have two answers.

If you apply the rules I've just given you, it should be pretty clear what the answers are. For instance, the first equation, $\sin A=0.7071$ , will have two solutions, but the second, $\cos A = -0.5$ , won't.

Can you do the rest of them now?

Grandad