trig equa solve for x: 2(sinx)^2 + 7sinx-4=0 between 0 and 2pi. How would yo go about doing this one>?
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Originally Posted by heatly trig equa solve for x: 2(sinx)^2 + 7sinx-4=0 between 0 and 2pi. How would yo go about doing this one>? try to un FOIL it the rest is easy... is undefined.
Last edited by bigwave; May 19th 2010 at 09:41 PM. Reason: more steps
Thank you very much,very good.
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