Normally i wouldn't ask someone to reply quickly, but my test i tomorrow
all help is gratfully appreiciated if you can answer it by midnight
I have made a picture of my problem.
Read this Intersecting Chord Theorem - Math Open Reference
Therefore in question 2: $\displaystyle 2\times 5 = x(2x+1)$
Solve for $\displaystyle x$.
Sorry i did not have tiime to explain my attempt:
5x2 =x(2x+1)
10 = 2x^2 + x
0 = 2x^2 + x - 10
2 / 0 = 2 / (x^2 + x - 10)
0 = x^2 + x - 10
0 = (x -10) (x + 1)
(split into two equation)
x = 10 <---
x = -1
In the end im left with x = 10, when in my textbook x = 2 ?