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Math Help - Another prove: double angles

  1. #1
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    Another prove: double angles

    So here's another problem that's been puzzling me for a couple hours. I got my answer as

    ---1---- does not equal--- 1--- but I am very unsure whether this is right
    4cos^2x---------------cos^2x
    Here's the question
    Prove that:
    2csc2xtanx=sec^2x
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  2. #2
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    Quote Originally Posted by tallguywhoplaysguitar View Post
    So here's another problem that's been puzzling me for a couple hours. I got my answer as

    ---1---- does not equal--- 1--- but I am very unsure whether this is right
    4cos^2x---------------cos^2x
    Here's the question
    Prove that:
    2csc2xtanx=sec^2x
    2\csc(2x)\tan{x} =

    \frac{2}{\sin(2x)} \cdot \frac{\sin{x}}{\cos{x}} = <br />

    \frac{2}{2\sin{x}\cos{x}} \cdot \frac{\sin{x}}{\cos{x}}

    finish it ...
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  3. #3
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    thanks, I was getting it wrong in the first step by placing the 2 in the denominator
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