Thanks, I hope that is it, i don't really have any other options whatsoever
and i have another one I can not quite understand
sin2x+cosx=0
and 2sinx - cos2^x - 2=0
Thanks, I hope that is it, i don't really have any other options whatsoever
and i have another one I can not quite understand
sin2x+cosx=0
and 2sinx - cos2^x - 2=0
$\displaystyle \sin(2x) = 2\sin{x}\cos{x}$ ... substitute, factor, and solve.