|sin (x+ pi/3)| = cos (x- pi/3)

sin (x+ pi/3) = cos (x- pi/3) sin (x+ pi/3) =- cos (x- pi/3)

thats how far i understand (Worried)

cos( pi/2- (x+ pi/3)) = cos (x- pi/3) (Doh)

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- May 11th 2010, 10:12 AMRukiChareduce with module?
|sin (x+ pi/3)| = cos (x- pi/3)

sin (x+ pi/3) = cos (x- pi/3) sin (x+ pi/3) =- cos (x- pi/3)

thats how far i understand (Worried)

cos( pi/2- (x+ pi/3)) = cos (x- pi/3) (Doh) - May 11th 2010, 02:29 PMmohammadfawaz
I think your question is not very clear...can you please clarify what's the question?