(secx - tanx)^2 + 1 -------------------- = 2 tanx secxcscx - tanxcscx HELP!!!
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Originally Posted by nee (secx - tanx)^2 + 1 -------------------- = 2 tanx secxcscx - tanxcscx HELP!!! $\displaystyle \frac{\sec^2{x} - 2\sec{x}\tan{x} + \tan^2{x}+1}{\csc{x}(\sec{x}-\tan{x})}$ $\displaystyle \frac{2\sec^2{x} - 2\sec{x}\tan{x}}{\csc{x}(\sec{x}-\tan{x})}$ $\displaystyle \frac{2\sec{x}(\sec{x} - \tan{x})}{\csc{x}(\sec{x}-\tan{x})}$ finish it ...
2secx ------- cscx 2(1/cosx) --------- 1/sinx 2sinx ----- cosx = 2tanx THANKS!!!
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